Giải:
C%CuSO4(95'C)=(87,7x100):(87,7+100)=46,7%
C%CuSO4(25'C)=(40x100):(40+100)=28.6%
1877gddCuSO4(46,7%) ___________________28,6-64
__________________________-28,6% ________________________
-xgCuSO4.5H2O(64%) ____________________ 46,7-28,6
Ta có:
1877:x=35,4:18,1
Vậy x=18,1x1877:35,4=958,7g
m CuSO4.5H2O kết tinh=958,7g